Permutations and Combinations
8. Application in Geometry
8.3. Diagonals in a polygon
We know that total number of vertices in a polygon having \(n\) sides, is \(n\). Hence total number of lines which can be formed by joining any two points = \(^n{{\rm{C}}_2}\), and of these lines n are sides of polygons, hence number of diagonals = \(^n{{\rm{C}}_2} - n\) = \(\frac{{n(n - 3)}}{2}\)
Consider a convex hexagon, there are 6 vertices and 6 sides. Total number of line segments that can be formed by connecting these vertices = \(^6{{\rm{C}}_2} = 15\), but out of these 15 line segments, 6 are sides of the hexagon, and the remaining 9 are the diagonals, shown in green colour.
Example 01: Number of diagonals in a convex polygon is four times the number of sides. Find the number of sides in the polygon.
Since number of diagonal = \(\cfrac{{n(n - 3)}}{2}\)
According to the question \(\cfrac{{n(n - 3)}}{2}=4n\) or \(n=11\)
According to the question \(\cfrac{{n(n - 3)}}{2}=4n\) or \(n=11\)